Base | Representation |
---|---|
bin | 10000010101010110110… |
… | …100010010010001000101 |
3 | 10222022012222112212020121 |
4 | 100111112310102101011 |
5 | 121342230402324031 |
6 | 2215350533101541 |
7 | 144044120113624 |
oct | 20252664222105 |
9 | 3868188485217 |
10 | 1122443011141 |
11 | 3a30308aa491 |
12 | 161653a878b1 |
13 | 81acc64ab1a |
14 | 3c4800076bb |
15 | 1e2e5e3c011 |
hex | 10556d12445 |
1122443011141 has 4 divisors (see below), whose sum is σ = 1124292176512. Its totient is φ = 1120593845772.
The previous prime is 1122443011061. The next prime is 1122443011147. The reversal of 1122443011141 is 1411103442211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1122443011141 - 215 = 1122442978373 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1122443011147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 924581775 + ... + 924582988.
It is an arithmetic number, because the mean of its divisors is an integer number (281073044128).
Almost surely, 21122443011141 is an apocalyptic number.
It is an amenable number.
1122443011141 is a deficient number, since it is larger than the sum of its proper divisors (1849165371).
1122443011141 is an equidigital number, since it uses as much as digits as its factorization.
1122443011141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1849165370.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 1122443011141 its reverse (1411103442211), we get a palindrome (2533546453352).
The spelling of 1122443011141 in words is "one trillion, one hundred twenty-two billion, four hundred forty-three million, eleven thousand, one hundred forty-one".
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