Base | Representation |
---|---|
bin | 1010001101010110100001… |
… | …0111000101010111100101 |
3 | 1110202001101201210222012220 |
4 | 2203111220113011113211 |
5 | 2432400234102114323 |
6 | 35512244142502553 |
7 | 2235641404261344 |
oct | 243255027052745 |
9 | 43661351728186 |
10 | 11224500426213 |
11 | 3638313960a38 |
12 | 1313472594a59 |
13 | 635609613639 |
14 | 2ab3a9519b5b |
15 | 146e95a1e0e3 |
hex | a35685c55e5 |
11224500426213 has 32 divisors (see below), whose sum is σ = 15932459980800. Its totient is φ = 7008727017600.
The previous prime is 11224500426211. The next prime is 11224500426233. The reversal of 11224500426213 is 31262400542211.
11224500426213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11224500426213 - 21 = 11224500426211 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11224500426211) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 47421028 + ... + 47657138.
It is an arithmetic number, because the mean of its divisors is an integer number (497889374400).
Almost surely, 211224500426213 is an apocalyptic number.
It is an amenable number.
11224500426213 is a deficient number, since it is larger than the sum of its proper divisors (4707959554587).
11224500426213 is a wasteful number, since it uses less digits than its factorization.
11224500426213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 245593.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 11224500426213 its reverse (31262400542211), we get a palindrome (42486900968424).
The spelling of 11224500426213 in words is "eleven trillion, two hundred twenty-four billion, five hundred million, four hundred twenty-six thousand, two hundred thirteen".
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