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1123001001307 is a prime number
BaseRepresentation
bin10000010101111000000…
…100110110010101011011
310222100122212111200212001
4100111320010312111123
5121344401224020212
62215522144501431
7144064004004253
oct20257004662533
93870585450761
101123001001307
113a3297874789
1216178a91a877
1381b8b128113
143c4d4176963
151e329e0c657
hex1057813655b

1123001001307 has 2 divisors, whose sum is σ = 1123001001308. Its totient is φ = 1123001001306.

The previous prime is 1123001001299. The next prime is 1123001001313. The reversal of 1123001001307 is 7031001003211.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1123001001307 - 23 = 1123001001299 is a prime.

It is a super-2 number, since 2×11230010013072 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1123001001607) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561500500653 + 561500500654.

It is an arithmetic number, because the mean of its divisors is an integer number (561500500654).

Almost surely, 21123001001307 is an apocalyptic number.

1123001001307 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123001001307 is an equidigital number, since it uses as much as digits as its factorization.

1123001001307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 126, while the sum is 19.

Adding to 1123001001307 its reverse (7031001003211), we get a palindrome (8154002004518).

The spelling of 1123001001307 in words is "one trillion, one hundred twenty-three billion, one million, one thousand, three hundred seven".