Base | Representation |
---|---|
bin | 10000010101111000000… |
… | …100110110010101011011 |
3 | 10222100122212111200212001 |
4 | 100111320010312111123 |
5 | 121344401224020212 |
6 | 2215522144501431 |
7 | 144064004004253 |
oct | 20257004662533 |
9 | 3870585450761 |
10 | 1123001001307 |
11 | 3a3297874789 |
12 | 16178a91a877 |
13 | 81b8b128113 |
14 | 3c4d4176963 |
15 | 1e329e0c657 |
hex | 1057813655b |
1123001001307 has 2 divisors, whose sum is σ = 1123001001308. Its totient is φ = 1123001001306.
The previous prime is 1123001001299. The next prime is 1123001001313. The reversal of 1123001001307 is 7031001003211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1123001001307 - 23 = 1123001001299 is a prime.
It is a super-2 number, since 2×11230010013072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1123001001607) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561500500653 + 561500500654.
It is an arithmetic number, because the mean of its divisors is an integer number (561500500654).
Almost surely, 21123001001307 is an apocalyptic number.
1123001001307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123001001307 is an equidigital number, since it uses as much as digits as its factorization.
1123001001307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 126, while the sum is 19.
Adding to 1123001001307 its reverse (7031001003211), we get a palindrome (8154002004518).
The spelling of 1123001001307 in words is "one trillion, one hundred twenty-three billion, one million, one thousand, three hundred seven".
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