Base | Representation |
---|---|
bin | 10100111010101110… |
… | …10101100010110001 |
3 | 1001222122100220212211 |
4 | 22131113111202301 |
5 | 140444344400212 |
6 | 5054203252121 |
7 | 545202030415 |
oct | 123527254261 |
9 | 31878326784 |
10 | 11230075057 |
11 | 48430a2673 |
12 | 2214b1a041 |
13 | 109c7b1b36 |
14 | 787680d45 |
15 | 45ad899a7 |
hex | 29d5d58b1 |
11230075057 has 2 divisors, whose sum is σ = 11230075058. Its totient is φ = 11230075056.
The previous prime is 11230074983. The next prime is 11230075069. The reversal of 11230075057 is 75057003211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10957693041 + 272382016 = 104679^2 + 16504^2 .
It is a cyclic number.
It is not a de Polignac number, because 11230075057 - 231 = 9082591409 is a prime.
It is a super-2 number, since 2×112300750572 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11230085057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615037528 + 5615037529.
It is an arithmetic number, because the mean of its divisors is an integer number (5615037529).
Almost surely, 211230075057 is an apocalyptic number.
It is an amenable number.
11230075057 is a deficient number, since it is larger than the sum of its proper divisors (1).
11230075057 is an equidigital number, since it uses as much as digits as its factorization.
11230075057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7350, while the sum is 31.
Adding to 11230075057 its reverse (75057003211), we get a palindrome (86287078268).
The spelling of 11230075057 in words is "eleven billion, two hundred thirty million, seventy-five thousand, fifty-seven".
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