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1123015065097 is a prime number
BaseRepresentation
bin10000010101111000111…
…010011111111000001001
310222100200211222012202011
4100111320322133320021
5121344413324040342
62215523410135521
7144064234360462
oct20257072377011
93870624865664
101123015065097
113a32a4800052
121617935815a1
1381b910105a3
143c4d5d97d69
151e32b289717
hex10578e9fe09

1123015065097 has 2 divisors, whose sum is σ = 1123015065098. Its totient is φ = 1123015065096.

The previous prime is 1123015065079. The next prime is 1123015065163. The reversal of 1123015065097 is 7905605103211.

Together with previous prime (1123015065079) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 562884065536 + 560130999561 = 750256^2 + 748419^2 .

It is an emirp because it is prime and its reverse (7905605103211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1123015065097 is a prime.

It is a super-2 number, since 2×11230150650972 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1123015065077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561507532548 + 561507532549.

It is an arithmetic number, because the mean of its divisors is an integer number (561507532549).

Almost surely, 21123015065097 is an apocalyptic number.

It is an amenable number.

1123015065097 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123015065097 is an equidigital number, since it uses as much as digits as its factorization.

1123015065097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56700, while the sum is 40.

The spelling of 1123015065097 in words is "one trillion, one hundred twenty-three billion, fifteen million, sixty-five thousand, ninety-seven".