Base | Representation |
---|---|
bin | 11001100010001101100110… |
… | …100101111100010111011101 |
3 | 112201121222200120112211220221 |
4 | 121202031212211330113131 |
5 | 104204424432131024013 |
6 | 1034502533250241341 |
7 | 32440365656213410 |
oct | 3142154645742735 |
9 | 481558616484827 |
10 | 112302231111133 |
11 | 32868121827078 |
12 | 10718b11b86251 |
13 | 4a8809396971b |
14 | 1da3657d8bb77 |
15 | ceb38abb408d |
hex | 66236697c5dd |
112302231111133 has 4 divisors (see below), whose sum is σ = 128345406984160. Its totient is φ = 96259055238108.
The previous prime is 112302231111131. The next prime is 112302231111157. The reversal of 112302231111133 is 331111132203211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 112302231111133 - 21 = 112302231111131 is a prime.
It is a super-2 number, since 2×1123022311111332 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 112302231111098 and 112302231111107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112302231111131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8021587936503 + ... + 8021587936516.
It is an arithmetic number, because the mean of its divisors is an integer number (32086351746040).
Almost surely, 2112302231111133 is an apocalyptic number.
It is an amenable number.
112302231111133 is a deficient number, since it is larger than the sum of its proper divisors (16043175873027).
112302231111133 is an equidigital number, since it uses as much as digits as its factorization.
112302231111133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16043175873026.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 112302231111133 its reverse (331111132203211), we get a palindrome (443413363314344).
The spelling of 112302231111133 in words is "one hundred twelve trillion, three hundred two billion, two hundred thirty-one million, one hundred eleven thousand, one hundred thirty-three".
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