Base | Representation |
---|---|
bin | 1010001101101100001101… |
… | …1011001101010100010110 |
3 | 1110202121102112101121000112 |
4 | 2203123003123031110112 |
5 | 2432444200214420202 |
6 | 35515050025043022 |
7 | 2236235610120122 |
oct | 243330333152426 |
9 | 43677375347015 |
10 | 11230323201302 |
11 | 363a831745057 |
12 | 1314618626472 |
13 | 636026a6a69a |
14 | 2ab79c994582 |
15 | 1471d6ceab52 |
hex | a36c36cd516 |
11230323201302 has 4 divisors (see below), whose sum is σ = 16845484801956. Its totient is φ = 5615161600650.
The previous prime is 11230323201263. The next prime is 11230323201311. The reversal of 11230323201302 is 20310232303211.
11230323201302 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×112303232013022 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2807580800324 + ... + 2807580800327.
It is an arithmetic number, because the mean of its divisors is an integer number (4211371200489).
Almost surely, 211230323201302 is an apocalyptic number.
11230323201302 is a deficient number, since it is larger than the sum of its proper divisors (5615161600654).
11230323201302 is an equidigital number, since it uses as much as digits as its factorization.
11230323201302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5615161600653.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 11230323201302 its reverse (20310232303211), we get a palindrome (31540555504513).
The spelling of 11230323201302 in words is "eleven trillion, two hundred thirty billion, three hundred twenty-three million, two hundred one thousand, three hundred two".
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