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11231000113 is a prime number
BaseRepresentation
bin10100111010110101…
…10111011000110001
31001222201002220211011
422131122313120301
5141000114000423
65054235150521
7545212632364
oct123532673061
931881086734
1011231000113
114843674683
1222152a5441
13109ca46bc8
147878420db
1545aebdb0d
hex29d6b7631

11231000113 has 2 divisors, whose sum is σ = 11231000114. Its totient is φ = 11231000112.

The previous prime is 11231000087. The next prime is 11231000129. The reversal of 11231000113 is 31100013211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8771633649 + 2459366464 = 93657^2 + 49592^2 .

It is a cyclic number.

It is not a de Polignac number, because 11231000113 - 213 = 11230991921 is a prime.

It is a super-2 number, since 2×112310001132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11231000093 and 11231000102.

It is not a weakly prime, because it can be changed into another prime (11231009113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615500056 + 5615500057.

It is an arithmetic number, because the mean of its divisors is an integer number (5615500057).

Almost surely, 211231000113 is an apocalyptic number.

It is an amenable number.

11231000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11231000113 is an equidigital number, since it uses as much as digits as its factorization.

11231000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11231000113 its reverse (31100013211), we get a palindrome (42331013324).

The spelling of 11231000113 in words is "eleven billion, two hundred thirty-one million, one hundred thirteen", and thus it is an aban number.