Base | Representation |
---|---|
bin | 10000010101111110000… |
… | …000001001111011011101 |
3 | 10222100220210121102001121 |
4 | 100111332000021323131 |
5 | 121400102202343031 |
6 | 2215540100010541 |
7 | 144066322115020 |
oct | 20257600117335 |
9 | 3870823542047 |
10 | 1123100434141 |
11 | 3a3338a09084 |
12 | 1617b8090a51 |
13 | 81ba590070a |
14 | 3c50345b1b7 |
15 | 1e3339ee011 |
hex | 1057e009edd |
1123100434141 has 8 divisors (see below), whose sum is σ = 1284298836800. Its totient is φ = 962090902368.
The previous prime is 1123100434117. The next prime is 1123100434189. The reversal of 1123100434141 is 1414340013211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1123100434141 - 25 = 1123100434109 is a prime.
It is a super-2 number, since 2×11231004341412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1123100434441) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47204976 + ... + 47228761.
It is an arithmetic number, because the mean of its divisors is an integer number (160537354600).
Almost surely, 21123100434141 is an apocalyptic number.
It is an amenable number.
1123100434141 is a deficient number, since it is larger than the sum of its proper divisors (161198402659).
1123100434141 is an equidigital number, since it uses as much as digits as its factorization.
1123100434141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94435443.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1123100434141 its reverse (1414340013211), we get a palindrome (2537440447352).
The spelling of 1123100434141 in words is "one trillion, one hundred twenty-three billion, one hundred million, four hundred thirty-four thousand, one hundred forty-one".
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