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1123101433 is a prime number
BaseRepresentation
bin100001011110001…
…0010101011111001
32220021022110112101
41002330102223321
54300003221213
6303235543401
736555130126
oct10274225371
92807273471
101123101433
11526a63803
1227415ab61
1314b8ab97c
14a923374d
15688eabdd
hex42f12af9

1123101433 has 2 divisors, whose sum is σ = 1123101434. Its totient is φ = 1123101432.

The previous prime is 1123101407. The next prime is 1123101437. The reversal of 1123101433 is 3341013211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 851939344 + 271162089 = 29188^2 + 16467^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1123101433 is a prime.

It is a super-2 number, since 2×11231014332 = 2522713657613306978, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1123101433.

It is not a weakly prime, because it can be changed into another prime (1123101437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561550716 + 561550717.

It is an arithmetic number, because the mean of its divisors is an integer number (561550717).

Almost surely, 21123101433 is an apocalyptic number.

It is an amenable number.

1123101433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123101433 is an equidigital number, since it uses as much as digits as its factorization.

1123101433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1123101433 is about 33512.7055458075. The cubic root of 1123101433 is about 1039.4565186143.

Adding to 1123101433 its reverse (3341013211), we get a palindrome (4464114644).

The spelling of 1123101433 in words is "one billion, one hundred twenty-three million, one hundred one thousand, four hundred thirty-three".