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11231224287 = 319918812771
BaseRepresentation
bin10100111010110111…
…01110000111011111
31001222201112022022220
422131123232013133
5141000143134122
65054244040423
7545214555063
oct123533560737
931881468286
1011231224287
114843808048
122215393113
13109cac4c5a
1478789daa3
1545b01525c
hex29d6ee1df

11231224287 has 8 divisors (see below), whose sum is σ = 15050217600. Its totient is φ = 7449856920.

The previous prime is 11231224283. The next prime is 11231224357. The reversal of 11231224287 is 78242213211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11231224287 - 22 = 11231224283 is a prime.

It is a super-3 number, since 3×112312242873 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11231224283) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9405789 + ... + 9406982.

It is an arithmetic number, because the mean of its divisors is an integer number (1881277200).

Almost surely, 211231224287 is an apocalyptic number.

11231224287 is a deficient number, since it is larger than the sum of its proper divisors (3818993313).

11231224287 is a wasteful number, since it uses less digits than its factorization.

11231224287 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18812973.

The product of its digits is 10752, while the sum is 33.

Adding to 11231224287 its reverse (78242213211), we get a palindrome (89473437498).

The spelling of 11231224287 in words is "eleven billion, two hundred thirty-one million, two hundred twenty-four thousand, two hundred eighty-seven".

Divisors: 1 3 199 597 18812771 56438313 3743741429 11231224287