Base | Representation |
---|---|
bin | 11001100010011111000101… |
… | …011011010001010010100001 |
3 | 112201200210010202022201022001 |
4 | 121202133011123101102201 |
5 | 104210231403004033303 |
6 | 1034515320032044001 |
7 | 32441632065251311 |
oct | 3142370533212241 |
9 | 481623122281261 |
10 | 112321002017953 |
11 | 32875084489203 |
12 | 10720690393601 |
13 | 4a89a95804891 |
14 | 1da4518d2d441 |
15 | cebad8a9931d |
hex | 6627c56d14a1 |
112321002017953 has 2 divisors, whose sum is σ = 112321002017954. Its totient is φ = 112321002017952.
The previous prime is 112321002017909. The next prime is 112321002018091. The reversal of 112321002017953 is 359710200123211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 57396124496529 + 54924877521424 = 7576023^2 + 7411132^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112321002017953 is a prime.
It is not a weakly prime, because it can be changed into another prime (112321002017153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56160501008976 + 56160501008977.
It is an arithmetic number, because the mean of its divisors is an integer number (56160501008977).
Almost surely, 2112321002017953 is an apocalyptic number.
It is an amenable number.
112321002017953 is a deficient number, since it is larger than the sum of its proper divisors (1).
112321002017953 is an equidigital number, since it uses as much as digits as its factorization.
112321002017953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 37.
The spelling of 112321002017953 in words is "one hundred twelve trillion, three hundred twenty-one billion, two million, seventeen thousand, nine hundred fifty-three".
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