Base | Representation |
---|---|
bin | 10000010110001001111… |
… | …001100011101010011011 |
3 | 10222101102201011222122201 |
4 | 100112021321203222123 |
5 | 121401004301444011 |
6 | 2220011550031031 |
7 | 144104264503315 |
oct | 20261171435233 |
9 | 3871381158581 |
10 | 1123300031131 |
11 | 3a3430646273 |
12 | 161852aa8477 |
13 | 81c08076445 |
14 | 3c521b767b5 |
15 | 1e3462c8cc1 |
hex | 10589e63a9b |
1123300031131 has 2 divisors, whose sum is σ = 1123300031132. Its totient is φ = 1123300031130.
The previous prime is 1123300031093. The next prime is 1123300031141. The reversal of 1123300031131 is 1311300033211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1123300031131 - 213 = 1123300022939 is a prime.
It is a super-2 number, since 2×11233000311312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1123300031099 and 1123300031108.
It is not a weakly prime, because it can be changed into another prime (1123300031141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561650015565 + 561650015566.
It is an arithmetic number, because the mean of its divisors is an integer number (561650015566).
Almost surely, 21123300031131 is an apocalyptic number.
1123300031131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123300031131 is an equidigital number, since it uses as much as digits as its factorization.
1123300031131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1123300031131 its reverse (1311300033211), we get a palindrome (2434600064342).
The spelling of 1123300031131 in words is "one trillion, one hundred twenty-three billion, three hundred million, thirty-one thousand, one hundred thirty-one".
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