11233121131 has 2 divisors, whose sum is σ = 11233121132. Its totient is φ = 11233121130.

The previous prime is 11233121117. The next prime is 11233121149. The reversal of 11233121131 is 13112133211.

It is a weak prime.

It is an emirp because it is prime and its reverse (13112133211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11233121131 - 2¹⁷ = 11232990059 is a prime.

It is a super-2 number, since 2×11233121131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11233121099 and 11233121108.

It is not a weakly prime, because it can be changed into another prime (11233121111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5616560565 + 5616560566.

It is an arithmetic number, because the mean of its divisors is an integer number (5616560566).

Almost surely, 2^11233121131 is an apocalyptic number.

11233121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11233121131 is an equidigital number, since it uses as much as digits as its factorization.

11233121131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 108, while the sum is 19.

Adding to 11233121131 its reverse (13112133211), we get a palindrome (24345254342).

The spelling of 11233121131 in words is "eleven billion, two hundred thirty-three million, one hundred twenty-one thousand, one hundred thirty-one".