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11233140132 = 2231914901021
BaseRepresentation
bin10100111011000110…
…00001110110100100
31001222212010122101010
422131203001312210
5141001140441012
65054353102220
7545240054454
oct123543016644
931885118333
1011233140132
1148448a6495
122215b57970
1310a0315ca6
14787c3bd64
1545b292c3c
hex29d8c1da4

11233140132 has 24 divisors (see below), whose sum is σ = 26347894272. Its totient is φ = 3724775200.

The previous prime is 11233139989. The next prime is 11233140137. The reversal of 11233140132 is 23104133211.

It is a junction number, because it is equal to n+sod(n) for n = 11233140099 and 11233140108.

It is not an unprimeable number, because it can be changed into a prime (11233140137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2448219 + ... + 2452802.

It is an arithmetic number, because the mean of its divisors is an integer number (1097828928).

Almost surely, 211233140132 is an apocalyptic number.

11233140132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11233140132 is an abundant number, since it is smaller than the sum of its proper divisors (15114754140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11233140132 is a wasteful number, since it uses less digits than its factorization.

11233140132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4901219 (or 4901217 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11233140132 its reverse (23104133211), we get a palindrome (34337273343).

The spelling of 11233140132 in words is "eleven billion, two hundred thirty-three million, one hundred forty thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 191 382 573 764 1146 2292 4901021 9802042 14703063 19604084 29406126 58812252 936095011 1872190022 2808285033 3744380044 5616570066 11233140132