Base | Representation |
---|---|
bin | 110100010011111111… |
… | …1110111100111111111 |
3 | 101201222011220122210110 |
4 | 1220213333313213333 |
5 | 3320033043012111 |
6 | 123335224241103 |
7 | 11054615656506 |
oct | 1504777674777 |
9 | 351864818713 |
10 | 112340204031 |
11 | 43709131030 |
12 | 19932610193 |
13 | a7942aa713 |
14 | 5619d1983d |
15 | 2dc77ab5a6 |
hex | 1a27ff79ff |
112340204031 has 64 divisors (see below), whose sum is σ = 176966000640. Its totient is φ = 62673072000.
The previous prime is 112340204027. The next prime is 112340204101. The reversal of 112340204031 is 130402043211.
It is not a de Polignac number, because 112340204031 - 22 = 112340204027 is a prime.
It is a super-2 number, since 2×1123402040312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 112340203989 and 112340204007.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112340204131) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6837216 + ... + 6853626.
It is an arithmetic number, because the mean of its divisors is an integer number (2765093760).
Almost surely, 2112340204031 is an apocalyptic number.
112340204031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
112340204031 is a deficient number, since it is larger than the sum of its proper divisors (64625796609).
112340204031 is a wasteful number, since it uses less digits than its factorization.
112340204031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16788.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 112340204031 its reverse (130402043211), we get a palindrome (242742247242).
The spelling of 112340204031 in words is "one hundred twelve billion, three hundred forty million, two hundred four thousand, thirty-one".
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