Base | Representation |
---|---|
bin | 1010001101111010000001… |
… | …1000110101010000100011 |
3 | 1110202221222220000220200102 |
4 | 2203132200120311100203 |
5 | 2433024243231440303 |
6 | 35520501534013015 |
7 | 2236426513241033 |
oct | 243364030652043 |
9 | 43687886026612 |
10 | 11234030343203 |
11 | 3641364292698 |
12 | 131529204716b |
13 | 636497ac1c85 |
14 | 2aba310738c3 |
15 | 1473524c3288 |
hex | a37a0635423 |
11234030343203 has 2 divisors, whose sum is σ = 11234030343204. Its totient is φ = 11234030343202.
The previous prime is 11234030343191. The next prime is 11234030343241. The reversal of 11234030343203 is 30234303043211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11234030343203 - 212 = 11234030339107 is a prime.
It is a super-3 number, since 3×112340303432033 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11234030345203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617015171601 + 5617015171602.
It is an arithmetic number, because the mean of its divisors is an integer number (5617015171602).
Almost surely, 211234030343203 is an apocalyptic number.
11234030343203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11234030343203 is an equidigital number, since it uses as much as digits as its factorization.
11234030343203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 11234030343203 its reverse (30234303043211), we get a palindrome (41468333386414).
The spelling of 11234030343203 in words is "eleven trillion, two hundred thirty-four billion, thirty million, three hundred forty-three thousand, two hundred three".
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