1123413033019 has 2 divisors, whose sum is σ = 1123413033020. Its totient is φ = 1123413033018.

The previous prime is 1123413032993. The next prime is 1123413033037. The reversal of 1123413033019 is 9103303143211.

It is a strong prime.

It is an emirp because it is prime and its reverse (9103303143211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1123413033019 - 2⁷ = 1123413032891 is a prime.

It is a super-3 number, since 3×1123413033019³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1123413033049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561706516509 + 561706516510.

It is an arithmetic number, because the mean of its divisors is an integer number (561706516510).

Almost surely, 2^{1123413033019} is an apocalyptic number.

1123413033019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123413033019 is an equidigital number, since it uses as much as digits as its factorization.

1123413033019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 31.

The spelling of 1123413033019 in words is "one trillion, one hundred twenty-three billion, four hundred thirteen million, thirty-three thousand, nineteen".