1123413044113 has 2 divisors, whose sum is σ = 1123413044114. Its totient is φ = 1123413044112.

The previous prime is 1123413044069. The next prime is 1123413044119. The reversal of 1123413044113 is 3114403143211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 702590974849 + 420822069264 = 838207^2 + 648708^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1123413044113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1123413044119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561706522056 + 561706522057.

It is an arithmetic number, because the mean of its divisors is an integer number (561706522057).

Almost surely, 2^{1123413044113} is an apocalyptic number.

It is an amenable number.

1123413044113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123413044113 is an equidigital number, since it uses as much as digits as its factorization.

1123413044113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1123413044113 its reverse (3114403143211), we get a palindrome (4237816187324).

The spelling of 1123413044113 in words is "one trillion, one hundred twenty-three billion, four hundred thirteen million, forty-four thousand, one hundred thirteen".