112341324000233 has 2 divisors, whose sum is σ = 112341324000234. Its totient is φ = 112341324000232.

The previous prime is 112341324000229. The next prime is 112341324000271. The reversal of 112341324000233 is 332000423143211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106851150155689 + 5490173844544 = 10336883^2 + 2343112^2 .

It is a cyclic number.

It is not a de Polignac number, because 112341324000233 - 2² = 112341324000229 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112341324000196 and 112341324000205.

It is not a weakly prime, because it can be changed into another prime (112341324000293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56170662000116 + 56170662000117.

It is an arithmetic number, because the mean of its divisors is an integer number (56170662000117).

Almost surely, 2^{112341324000233} is an apocalyptic number.

It is an amenable number.

112341324000233 is a deficient number, since it is larger than the sum of its proper divisors (1).

112341324000233 is an equidigital number, since it uses as much as digits as its factorization.

112341324000233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 112341324000233 its reverse (332000423143211), we get a palindrome (444341747143444).

The spelling of 112341324000233 in words is "one hundred twelve trillion, three hundred forty-one billion, three hundred twenty-four million, two hundred thirty-three", and thus it is an aban number.