Base | Representation |
---|---|
bin | 1010001101111010101010… |
… | …0001001011110101110011 |
3 | 1110202222102201211212110012 |
4 | 2203132222201023311303 |
5 | 2433030120234230021 |
6 | 35520530444525135 |
7 | 2236433646010355 |
oct | 243365241136563 |
9 | 43688381755405 |
10 | 11234200305011 |
11 | 36414412194a2 |
12 | 131531ab507ab |
13 | 6364c408caa8 |
14 | 2aba498770d5 |
15 | 14736239735b |
hex | a37aa84bd73 |
11234200305011 has 2 divisors, whose sum is σ = 11234200305012. Its totient is φ = 11234200305010.
The previous prime is 11234200304947. The next prime is 11234200305019. The reversal of 11234200305011 is 11050300243211.
It is a strong prime.
It is an emirp because it is prime and its reverse (11050300243211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11234200305011 - 26 = 11234200304947 is a prime.
It is not a weakly prime, because it can be changed into another prime (11234200305019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617100152505 + 5617100152506.
It is an arithmetic number, because the mean of its divisors is an integer number (5617100152506).
Almost surely, 211234200305011 is an apocalyptic number.
11234200305011 is a deficient number, since it is larger than the sum of its proper divisors (1).
11234200305011 is an equidigital number, since it uses as much as digits as its factorization.
11234200305011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 11234200305011 its reverse (11050300243211), we get a palindrome (22284500548222).
The spelling of 11234200305011 in words is "eleven trillion, two hundred thirty-four billion, two hundred million, three hundred five thousand, eleven".
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