Base | Representation |
---|---|
bin | 10000010110010001000… |
… | …011010101100010110011 |
3 | 10222101202001222211100202 |
4 | 100112101003111202303 |
5 | 121401231012112001 |
6 | 2220031514105415 |
7 | 144110252512463 |
oct | 20262103254263 |
9 | 3871661884322 |
10 | 1123420035251 |
11 | 3a3492360128 |
12 | 16188711b26b |
13 | 81c26ba21b7 |
14 | 3c533a93ba3 |
15 | 1e351ad096b |
hex | 105910d58b3 |
1123420035251 has 2 divisors, whose sum is σ = 1123420035252. Its totient is φ = 1123420035250.
The previous prime is 1123420035203. The next prime is 1123420035277. The reversal of 1123420035251 is 1525300243211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1123420035251 - 210 = 1123420034227 is a prime.
It is not a weakly prime, because it can be changed into another prime (1123420035151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561710017625 + 561710017626.
It is an arithmetic number, because the mean of its divisors is an integer number (561710017626).
Almost surely, 21123420035251 is an apocalyptic number.
1123420035251 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123420035251 is an equidigital number, since it uses as much as digits as its factorization.
1123420035251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 1123420035251 its reverse (1525300243211), we get a palindrome (2648720278462).
The spelling of 1123420035251 in words is "one trillion, one hundred twenty-three billion, four hundred twenty million, thirty-five thousand, two hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •