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11234221413 = 33744740471
BaseRepresentation
bin10100111011001110…
…01001110101100101
31001222221011120121120
422131213021311211
5141001430041123
65054432204153
7545252210052
oct123547116545
931887146546
1011234221413
114845474908
122216399659
1310a06041bc
14788040029
1545b4082e3
hex29d9c9d65

11234221413 has 4 divisors (see below), whose sum is σ = 14978961888. Its totient is φ = 7489480940.

The previous prime is 11234221399. The next prime is 11234221421. The reversal of 11234221413 is 31412243211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11234221413 - 25 = 11234221381 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11234221613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1872370233 + ... + 1872370238.

It is an arithmetic number, because the mean of its divisors is an integer number (3744740472).

Almost surely, 211234221413 is an apocalyptic number.

It is an amenable number.

11234221413 is a deficient number, since it is larger than the sum of its proper divisors (3744740475).

11234221413 is an equidigital number, since it uses as much as digits as its factorization.

11234221413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3744740474.

The product of its digits is 1152, while the sum is 24.

Adding to 11234221413 its reverse (31412243211), we get a palindrome (42646464624).

The spelling of 11234221413 in words is "eleven billion, two hundred thirty-four million, two hundred twenty-one thousand, four hundred thirteen".

Divisors: 1 3 3744740471 11234221413