112343707393 has 2 divisors, whose sum is σ = 112343707394. Its totient is φ = 112343707392.

The previous prime is 112343707379. The next prime is 112343707417. The reversal of 112343707393 is 393707343211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104111411569 + 8232295824 = 322663^2 + 90732^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112343707393 is a prime.

It is a super-2 number, since 2×112343707393² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112343707313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56171853696 + 56171853697.

It is an arithmetic number, because the mean of its divisors is an integer number (56171853697).

Almost surely, 2^112343707393 is an apocalyptic number.

It is an amenable number.

112343707393 is a deficient number, since it is larger than the sum of its proper divisors (1).

112343707393 is an equidigital number, since it uses as much as digits as its factorization.

112343707393 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 285768, while the sum is 43.

The spelling of 112343707393 in words is "one hundred twelve billion, three hundred forty-three million, seven hundred seven thousand, three hundred ninety-three".