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11234414011993 is a prime number
BaseRepresentation
bin1010001101111011011101…
…0000011010011001011001
31110202222222121222022022121
42203132313100122121121
52433031034441340433
635521004001221241
72236442152333654
oct243366720323131
943688877868277
1011234414011993
113641540913737
12131537a631821
13636529436023
142aba69dc689b
1514737600cc2d
hexa37b741a659

11234414011993 has 2 divisors, whose sum is σ = 11234414011994. Its totient is φ = 11234414011992.

The previous prime is 11234414011949. The next prime is 11234414011999. The reversal of 11234414011993 is 39911041443211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9962778893769 + 1271635118224 = 3156387^2 + 1127668^2 .

It is a cyclic number.

It is not a de Polignac number, because 11234414011993 - 221 = 11234411914841 is a prime.

It is not a weakly prime, because it can be changed into another prime (11234414011999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617207005996 + 5617207005997.

It is an arithmetic number, because the mean of its divisors is an integer number (5617207005997).

Almost surely, 211234414011993 is an apocalyptic number.

It is an amenable number.

11234414011993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11234414011993 is an equidigital number, since it uses as much as digits as its factorization.

11234414011993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 43.

The spelling of 11234414011993 in words is "eleven trillion, two hundred thirty-four billion, four hundred fourteen million, eleven thousand, nine hundred ninety-three".