Base | Representation |
---|---|
bin | 11001100010110101110000… |
… | …111111011110100111010011 |
3 | 112201210002222222020002110012 |
4 | 121202311300333132213103 |
5 | 104211131241421001011 |
6 | 1034534424350225135 |
7 | 32443453430310233 |
oct | 3142656077364723 |
9 | 481702888202405 |
10 | 112345355250131 |
11 | 32884441223a73 |
12 | 107253481b51ab |
13 | 4a8c177049333 |
14 | 1da5789437cc3 |
15 | cec561ab1a8b |
hex | 662d70fde9d3 |
112345355250131 has 2 divisors, whose sum is σ = 112345355250132. Its totient is φ = 112345355250130.
The previous prime is 112345355250119. The next prime is 112345355250151. The reversal of 112345355250131 is 131052553543211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112345355250131 - 222 = 112345351055827 is a prime.
It is a super-2 number, since 2×1123453552501312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112345355250151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56172677625065 + 56172677625066.
It is an arithmetic number, because the mean of its divisors is an integer number (56172677625066).
Almost surely, 2112345355250131 is an apocalyptic number.
112345355250131 is a deficient number, since it is larger than the sum of its proper divisors (1).
112345355250131 is an equidigital number, since it uses as much as digits as its factorization.
112345355250131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270000, while the sum is 41.
The spelling of 112345355250131 in words is "one hundred twelve trillion, three hundred forty-five billion, three hundred fifty-five million, two hundred fifty thousand, one hundred thirty-one".
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