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1123455566713 is a prime number
BaseRepresentation
bin10000010110010011001…
…010111000001101111001
310222101211112212000100211
4100112103022320031321
5121401314111113323
62220035223431121
7144111163516654
oct20262312701571
93871745760324
101123455566713
113a3500419477
12161896bb54a1
1381c31362b2c
143c5386a289b
151e354c9d70d
hex105932b8379

1123455566713 has 2 divisors, whose sum is σ = 1123455566714. Its totient is φ = 1123455566712.

The previous prime is 1123455566641. The next prime is 1123455566759. The reversal of 1123455566713 is 3176655543211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1063874662249 + 59580904464 = 1031443^2 + 244092^2 .

It is a cyclic number.

It is not a de Polignac number, because 1123455566713 - 221 = 1123453469561 is a prime.

It is not a weakly prime, because it can be changed into another prime (1123455566813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561727783356 + 561727783357.

It is an arithmetic number, because the mean of its divisors is an integer number (561727783357).

Almost surely, 21123455566713 is an apocalyptic number.

It is an amenable number.

1123455566713 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123455566713 is an equidigital number, since it uses as much as digits as its factorization.

1123455566713 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2268000, while the sum is 49.

The spelling of 1123455566713 in words is "one trillion, one hundred twenty-three billion, four hundred fifty-five million, five hundred sixty-six thousand, seven hundred thirteen".