Base | Representation |
---|---|
bin | 110100010101110010… |
… | …0100110010011110001 |
3 | 101202010100201221112001 |
4 | 1220223210212103301 |
5 | 3320143420222311 |
6 | 123345205334001 |
7 | 11056244426242 |
oct | 1505344462361 |
9 | 352110657461 |
10 | 112400164081 |
11 | 43739a64997 |
12 | 1994a707301 |
13 | a7a384243a |
14 | 5623c86cc9 |
15 | 2dccba24c1 |
hex | 1a2b9264f1 |
112400164081 has 2 divisors, whose sum is σ = 112400164082. Its totient is φ = 112400164080.
The previous prime is 112400164057. The next prime is 112400164099. The reversal of 112400164081 is 180461004211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 84905218225 + 27494945856 = 291385^2 + 165816^2 .
It is a cyclic number.
It is not a de Polignac number, because 112400164081 - 25 = 112400164049 is a prime.
It is a super-2 number, since 2×1124001640812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112400164381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56200082040 + 56200082041.
It is an arithmetic number, because the mean of its divisors is an integer number (56200082041).
Almost surely, 2112400164081 is an apocalyptic number.
It is an amenable number.
112400164081 is a deficient number, since it is larger than the sum of its proper divisors (1).
112400164081 is an equidigital number, since it uses as much as digits as its factorization.
112400164081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 28.
Adding to 112400164081 its reverse (180461004211), we get a palindrome (292861168292).
The spelling of 112400164081 in words is "one hundred twelve billion, four hundred million, one hundred sixty-four thousand, eighty-one".
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