Base | Representation |
---|---|
bin | 10100111011111011… |
… | …00101000000001011 |
3 | 1002000100020020022111 |
4 | 22131331211000023 |
5 | 141004431143401 |
6 | 5055202203151 |
7 | 545353162261 |
oct | 123575450013 |
9 | 32010206274 |
10 | 11240099851 |
11 | 484881a422 |
12 | 22183534b7 |
13 | 10a18b1a76 |
14 | 788b30431 |
15 | 45bbb9e51 |
hex | 29df6500b |
11240099851 has 2 divisors, whose sum is σ = 11240099852. Its totient is φ = 11240099850.
The previous prime is 11240099837. The next prime is 11240099863. The reversal of 11240099851 is 15899004211.
11240099851 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (15899004211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11240099851 - 213 = 11240091659 is a prime.
It is not a weakly prime, because it can be changed into another prime (11240099881) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5620049925 + 5620049926.
It is an arithmetic number, because the mean of its divisors is an integer number (5620049926).
Almost surely, 211240099851 is an apocalyptic number.
11240099851 is a deficient number, since it is larger than the sum of its proper divisors (1).
11240099851 is an equidigital number, since it uses as much as digits as its factorization.
11240099851 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 40.
The spelling of 11240099851 in words is "eleven billion, two hundred forty million, ninety-nine thousand, eight hundred fifty-one".
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