Base | Representation |
---|---|
bin | 1010001110010000110000… |
… | …0110011100100010101001 |
3 | 1110210112202011012001002212 |
4 | 2203210030012130202221 |
5 | 2433124242400224433 |
6 | 35523351234534505 |
7 | 2240033650152365 |
oct | 243441406344251 |
9 | 43715664161085 |
10 | 11240132429993 |
11 | 3643a057aa825 |
12 | 13164b5737435 |
13 | 636c2b08230c |
14 | 2ac04d6582a5 |
15 | 1475ad073d48 |
hex | a390c19c8a9 |
11240132429993 has 2 divisors, whose sum is σ = 11240132429994. Its totient is φ = 11240132429992.
The previous prime is 11240132429989. The next prime is 11240132430017. The reversal of 11240132429993 is 39992423104211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9169074690304 + 2071057739689 = 3028048^2 + 1439117^2 .
It is a cyclic number.
It is not a de Polignac number, because 11240132429993 - 22 = 11240132429989 is a prime.
It is not a weakly prime, because it can be changed into another prime (11240132429893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5620066214996 + 5620066214997.
It is an arithmetic number, because the mean of its divisors is an integer number (5620066214997).
Almost surely, 211240132429993 is an apocalyptic number.
It is an amenable number.
11240132429993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11240132429993 is an equidigital number, since it uses as much as digits as its factorization.
11240132429993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 839808, while the sum is 50.
The spelling of 11240132429993 in words is "eleven trillion, two hundred forty billion, one hundred thirty-two million, four hundred twenty-nine thousand, nine hundred ninety-three".
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