Base | Representation |
---|---|
bin | 10100111011111100… |
… | …00000101111000001 |
3 | 1002000100110000010112 |
4 | 22131332000233001 |
5 | 141004443312231 |
6 | 5055204441105 |
7 | 545354144402 |
oct | 123576005701 |
9 | 32010400115 |
10 | 11240213441 |
11 | 48488977a6 |
12 | 22183a9195 |
13 | 10a1921692 |
14 | 788b5d9a9 |
15 | 45bbdd92b |
hex | 29df80bc1 |
11240213441 has 2 divisors, whose sum is σ = 11240213442. Its totient is φ = 11240213440.
The previous prime is 11240213431. The next prime is 11240213483. The reversal of 11240213441 is 14431204211.
11240213441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8148853441 + 3091360000 = 90271^2 + 55600^2 .
It is a cyclic number.
It is not a de Polignac number, because 11240213441 - 218 = 11239951297 is a prime.
It is not a weakly prime, because it can be changed into another prime (11240213431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5620106720 + 5620106721.
It is an arithmetic number, because the mean of its divisors is an integer number (5620106721).
Almost surely, 211240213441 is an apocalyptic number.
It is an amenable number.
11240213441 is a deficient number, since it is larger than the sum of its proper divisors (1).
11240213441 is an equidigital number, since it uses as much as digits as its factorization.
11240213441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 11240213441 its reverse (14431204211), we get a palindrome (25671417652).
The spelling of 11240213441 in words is "eleven billion, two hundred forty million, two hundred thirteen thousand, four hundred forty-one".
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