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112403310314031 = 32112235091421403
BaseRepresentation
bin11001100011101011101111…
…011000100000001000101111
3112201222122120221220101020100
4121203223233120200020233
5104213103434420022111
61035021211244322143
732450604546236142
oct3143535730401057
9481878527811210
10112403310314031
11328a6a813622a0
1210734621243353
134a94781c27959
141da84c6496059
15cedd04a27756
hex663aef62022f

112403310314031 has 24 divisors (see below), whose sum is σ = 177914629541376. Its totient is φ = 67817733074640.

The previous prime is 112403310314027. The next prime is 112403310314107. The reversal of 112403310314031 is 130413013304211.

112403310314031 is a `hidden beast` number, since 1 + 1 + 2 + 4 + 0 + 3 + 310 + 314 + 0 + 31 = 666.

It is not a de Polignac number, because 112403310314031 - 22 = 112403310314027 is a prime.

It is a super-3 number, since 3×1124033103140313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 112403310313986 and 112403310314004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112403310314021) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2545688625 + ... + 2545732778.

It is an arithmetic number, because the mean of its divisors is an integer number (7413109564224).

Almost surely, 2112403310314031 is an apocalyptic number.

112403310314031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

112403310314031 is a deficient number, since it is larger than the sum of its proper divisors (65511319227345).

112403310314031 is a wasteful number, since it uses less digits than its factorization.

112403310314031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5091421643 (or 5091421640 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 112403310314031 its reverse (130413013304211), we get a palindrome (242816323618242).

The spelling of 112403310314031 in words is "one hundred twelve trillion, four hundred three billion, three hundred ten million, three hundred fourteen thousand, thirty-one".

Divisors: 1 3 9 11 33 99 223 669 2007 2453 7359 22077 5091421403 15274264209 45822792627 56005635433 168016906299 504050718897 1135386972869 3406160918607 10218482755821 12489256701559 37467770104677 112403310314031