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1124113030234 = 2711197903043
BaseRepresentation
bin10000010110111010010…
…110111001110001011010
310222110112100222121202121
4100112322112321301122
5121404140413431414
62220224351251454
7144133366050145
oct20267226716132
93873470877677
101124113030234
113a3808555557
12161a3b219b8a
138200762acbc
143c59bb2705c
151e39286c724
hex105ba5b9c5a

1124113030234 has 8 divisors (see below), whose sum is σ = 1686193467840. Its totient is φ = 562048540956.

The previous prime is 1124113030231. The next prime is 1124113030241. The reversal of 1124113030234 is 4320303114211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1124113030199 and 1124113030208.

It is not an unprimeable number, because it can be changed into a prime (1124113030231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3809284 + ... + 4093759.

It is an arithmetic number, because the mean of its divisors is an integer number (210774183480).

Almost surely, 21124113030234 is an apocalyptic number.

1124113030234 is a deficient number, since it is larger than the sum of its proper divisors (562080437606).

1124113030234 is an equidigital number, since it uses as much as digits as its factorization.

1124113030234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7974164.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1124113030234 its reverse (4320303114211), we get a palindrome (5444416144445).

The spelling of 1124113030234 in words is "one trillion, one hundred twenty-four billion, one hundred thirteen million, thirty thousand, two hundred thirty-four".

Divisors: 1 2 71119 142238 7903043 15806086 562056515117 1124113030234