Search a number
-
+
112421355455 = 5199671223767
BaseRepresentation
bin110100010110011010…
…1011011111110111111
3101202011211121120121202
41220230311123332333
53320214331333310
6123351243450115
711056622516543
oct1505465337677
9352154546552
10112421355455
114374aa19322
121995582693b
13a7a8051c06
145626a01a23
152dce98b3a5
hex1a2cd5bfbf

112421355455 has 16 divisors (see below), whose sum is σ = 142152890880. Its totient is φ = 85115372832.

The previous prime is 112421355443. The next prime is 112421355457. The reversal of 112421355455 is 554553124211.

It is a cyclic number.

It is not a de Polignac number, because 112421355455 - 234 = 95241486271 is a prime.

It is a super-2 number, since 2×1124213554552 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112421355457) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 520019 + ... + 703748.

It is an arithmetic number, because the mean of its divisors is an integer number (8884555680).

Almost surely, 2112421355455 is an apocalyptic number.

112421355455 is a deficient number, since it is larger than the sum of its proper divisors (29731535425).

112421355455 is a wasteful number, since it uses less digits than its factorization.

112421355455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1224758.

The product of its digits is 120000, while the sum is 38.

Adding to 112421355455 its reverse (554553124211), we get a palindrome (666974479666).

The spelling of 112421355455 in words is "one hundred twelve billion, four hundred twenty-one million, three hundred fifty-five thousand, four hundred fifty-five".

Divisors: 1 5 19 95 967 4835 18373 91865 1223767 6118835 23251573 116257865 1183382689 5916913445 22484271091 112421355455