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11242220201347 is a prime number
BaseRepresentation
bin1010001110011000100010…
…0010101010010110000011
31110210202010122200210222211
42203212020202222112003
52433143031332420342
635524334335042551
72240136461005342
oct243461042522603
943722118623884
1011242220201347
1136448872462a3
121316998970457
136371a177b095
142ac1aaa3db59
151476814c2c17
hexa39888aa583

11242220201347 has 2 divisors, whose sum is σ = 11242220201348. Its totient is φ = 11242220201346.

The previous prime is 11242220201291. The next prime is 11242220201357. The reversal of 11242220201347 is 74310202224211.

It is a strong prime.

It is an emirp because it is prime and its reverse (74310202224211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11242220201347 is a prime.

It is a super-2 number, since 2×112422202013472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11242220201357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621110100673 + 5621110100674.

It is an arithmetic number, because the mean of its divisors is an integer number (5621110100674).

Almost surely, 211242220201347 is an apocalyptic number.

11242220201347 is a deficient number, since it is larger than the sum of its proper divisors (1).

11242220201347 is an equidigital number, since it uses as much as digits as its factorization.

11242220201347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10752, while the sum is 31.

Adding to 11242220201347 its reverse (74310202224211), we get a palindrome (85552422425558).

The spelling of 11242220201347 in words is "eleven trillion, two hundred forty-two billion, two hundred twenty million, two hundred one thousand, three hundred forty-seven".