Base | Representation |
---|---|
bin | 11001100011111110011101… |
… | …000111101100100001110111 |
3 | 112202001120110101121212012102 |
4 | 121203332131013230201313 |
5 | 104213421113140404421 |
6 | 1035034333235412315 |
7 | 32452215531326513 |
oct | 3143763507544167 |
9 | 482046411555172 |
10 | 112423405013111 |
11 | 32904553292115 |
12 | 107384aaa5409b |
13 | 4a9663510b33a |
14 | 1da947118d143 |
15 | cee5cdc4c60b |
hex | 663f9d1ec877 |
112423405013111 has 4 divisors (see below), whose sum is σ = 112741884914352. Its totient is φ = 112104925111872.
The previous prime is 112423405013071. The next prime is 112423405013119. The reversal of 112423405013111 is 111310504324211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112423405013111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112423405013119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159239950091 + ... + 159239950796.
It is an arithmetic number, because the mean of its divisors is an integer number (28185471228588).
Almost surely, 2112423405013111 is an apocalyptic number.
112423405013111 is a deficient number, since it is larger than the sum of its proper divisors (318479901241).
112423405013111 is an equidigital number, since it uses as much as digits as its factorization.
112423405013111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 318479901240.
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 112423405013111 its reverse (111310504324211), we get a palindrome (223733909337322).
The spelling of 112423405013111 in words is "one hundred twelve trillion, four hundred twenty-three billion, four hundred five million, thirteen thousand, one hundred eleven".
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