11243001113 has 2 divisors, whose sum is σ = 11243001114. Its totient is φ = 11243001112.

The previous prime is 11243001109. The next prime is 11243001163. The reversal of 11243001113 is 31110034211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8849541184 + 2393459929 = 94072^2 + 48923^2 .

It is an emirp because it is prime and its reverse (31110034211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11243001113 - 2² = 11243001109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11243001091 and 11243001100.

It is not a weakly prime, because it can be changed into another prime (11243001103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621500556 + 5621500557.

It is an arithmetic number, because the mean of its divisors is an integer number (5621500557).

Almost surely, 2^11243001113 is an apocalyptic number.

It is an amenable number.

11243001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11243001113 is an equidigital number, since it uses as much as digits as its factorization.

11243001113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11243001113 its reverse (31110034211), we get a palindrome (42353035324).

The spelling of 11243001113 in words is "eleven billion, two hundred forty-three million, one thousand, one hundred thirteen".