Base | Representation |
---|---|
bin | 11001100100000101100111… |
… | …111001011010011001111011 |
3 | 112202002022022210212212100102 |
4 | 121210011213321122121323 |
5 | 104214032344103323003 |
6 | 1035042045113030015 |
7 | 32452610342614556 |
oct | 3144054771323173 |
9 | 482068283785312 |
10 | 112431102011003 |
11 | 329078430155a6 |
12 | 10739a986b530b |
13 | 4a97290942069 |
14 | 1da99a150169d |
15 | cee8ce844588 |
hex | 664167e5a67b |
112431102011003 has 2 divisors, whose sum is σ = 112431102011004. Its totient is φ = 112431102011002.
The previous prime is 112431102010967. The next prime is 112431102011089. The reversal of 112431102011003 is 300110201134211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112431102011003 - 210 = 112431102009979 is a prime.
It is not a weakly prime, because it can be changed into another prime (112431102011203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56215551005501 + 56215551005502.
It is an arithmetic number, because the mean of its divisors is an integer number (56215551005502).
Almost surely, 2112431102011003 is an apocalyptic number.
112431102011003 is a deficient number, since it is larger than the sum of its proper divisors (1).
112431102011003 is an equidigital number, since it uses as much as digits as its factorization.
112431102011003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 112431102011003 its reverse (300110201134211), we get a palindrome (412541303145214).
The spelling of 112431102011003 in words is "one hundred twelve trillion, four hundred thirty-one billion, one hundred two million, eleven thousand, three".
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