Base | Representation |
---|---|
bin | 10100111100010011… |
… | …11000000000101001 |
3 | 1002000120022000020102 |
4 | 22132021320000221 |
5 | 141011242322213 |
6 | 5055355235145 |
7 | 545422446416 |
oct | 123611700051 |
9 | 32016260212 |
10 | 11243323433 |
11 | 484a621341 |
12 | 2219448ab5 |
13 | 10a2470104 |
14 | 78932d10d |
15 | 45c105158 |
hex | 29e278029 |
11243323433 has 2 divisors, whose sum is σ = 11243323434. Its totient is φ = 11243323432.
The previous prime is 11243323373. The next prime is 11243323471. The reversal of 11243323433 is 33432334211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10292711209 + 950612224 = 101453^2 + 30832^2 .
It is a cyclic number.
It is not a de Polignac number, because 11243323433 - 212 = 11243319337 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11243323396 and 11243323405.
It is not a weakly prime, because it can be changed into another prime (11243323633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621661716 + 5621661717.
It is an arithmetic number, because the mean of its divisors is an integer number (5621661717).
Almost surely, 211243323433 is an apocalyptic number.
It is an amenable number.
11243323433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11243323433 is an equidigital number, since it uses as much as digits as its factorization.
11243323433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15552, while the sum is 29.
Adding to 11243323433 its reverse (33432334211), we get a palindrome (44675657644).
The spelling of 11243323433 in words is "eleven billion, two hundred forty-three million, three hundred twenty-three thousand, four hundred thirty-three".
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