Base | Representation |
---|---|
bin | 11001100100001000011010… |
… | …101110010110010110000011 |
3 | 112202002121001220022220110022 |
4 | 121210020122232112112003 |
5 | 104214110020132414301 |
6 | 1035043302530124055 |
7 | 32453044603232066 |
oct | 3144103256262603 |
9 | 482077056286408 |
10 | 112434102232451 |
11 | 3290904261735a |
12 | 1073a59542062b |
13 | 4a9764b3a331c |
14 | 1da9ba7b648dd |
15 | ceea07e2dd1b |
hex | 66421ab96583 |
112434102232451 has 2 divisors, whose sum is σ = 112434102232452. Its totient is φ = 112434102232450.
The previous prime is 112434102232423. The next prime is 112434102232457. The reversal of 112434102232451 is 154232201434211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112434102232451 - 210 = 112434102231427 is a prime.
It is not a weakly prime, because it can be changed into another prime (112434102232457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56217051116225 + 56217051116226.
It is an arithmetic number, because the mean of its divisors is an integer number (56217051116226).
Almost surely, 2112434102232451 is an apocalyptic number.
112434102232451 is a deficient number, since it is larger than the sum of its proper divisors (1).
112434102232451 is an equidigital number, since it uses as much as digits as its factorization.
112434102232451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 112434102232451 its reverse (154232201434211), we get a palindrome (266666303666662).
The spelling of 112434102232451 in words is "one hundred twelve trillion, four hundred thirty-four billion, one hundred two million, two hundred thirty-two thousand, four hundred fifty-one".
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