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11243412137 is a prime number
BaseRepresentation
bin10100111100010100…
…01101101010101001
31002000120110111220202
422132022031222221
5141011303142022
65055401201545
7545423266136
oct123612155251
932016414822
1011243412137
11484a681a51
1222194902b5
1310a24a15b9
1478935358d
1545c121592
hex29e28daa9

11243412137 has 2 divisors, whose sum is σ = 11243412138. Its totient is φ = 11243412136.

The previous prime is 11243412121. The next prime is 11243412149. The reversal of 11243412137 is 73121434211.

11243412137 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6480894016 + 4762518121 = 80504^2 + 69011^2 .

It is a cyclic number.

It is not a de Polignac number, because 11243412137 - 24 = 11243412121 is a prime.

It is not a weakly prime, because it can be changed into another prime (11243412197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621706068 + 5621706069.

It is an arithmetic number, because the mean of its divisors is an integer number (5621706069).

Almost surely, 211243412137 is an apocalyptic number.

It is an amenable number.

11243412137 is a deficient number, since it is larger than the sum of its proper divisors (1).

11243412137 is an equidigital number, since it uses as much as digits as its factorization.

11243412137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4032, while the sum is 29.

Adding to 11243412137 its reverse (73121434211), we get a palindrome (84364846348).

The spelling of 11243412137 in words is "eleven billion, two hundred forty-three million, four hundred twelve thousand, one hundred thirty-seven".