Base | Representation |
---|---|
bin | 1010001110011111111100… |
… | …1110101000101011100001 |
3 | 1110210221021102120020101122 |
4 | 2203213333032220223201 |
5 | 2433211121112042403 |
6 | 35525304110142025 |
7 | 2240240020161023 |
oct | 243477716505341 |
9 | 43727242506348 |
10 | 11244211440353 |
11 | 3645709249671 |
12 | 13172537b1915 |
13 | 63742b178808 |
14 | 2ac319298013 |
15 | 14774b204838 |
hex | a39ff3a8ae1 |
11244211440353 has 2 divisors, whose sum is σ = 11244211440354. Its totient is φ = 11244211440352.
The previous prime is 11244211440313. The next prime is 11244211440431. The reversal of 11244211440353 is 35304411244211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10932168542689 + 312042897664 = 3306383^2 + 558608^2 .
It is a cyclic number.
It is not a de Polignac number, because 11244211440353 - 218 = 11244211178209 is a prime.
It is not a weakly prime, because it can be changed into another prime (11244211440313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5622105720176 + 5622105720177.
It is an arithmetic number, because the mean of its divisors is an integer number (5622105720177).
Almost surely, 211244211440353 is an apocalyptic number.
It is an amenable number.
11244211440353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11244211440353 is an equidigital number, since it uses as much as digits as its factorization.
11244211440353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 11244211440353 its reverse (35304411244211), we get a palindrome (46548622684564).
The spelling of 11244211440353 in words is "eleven trillion, two hundred forty-four billion, two hundred eleven million, four hundred forty thousand, three hundred fifty-three".
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