| Base | Representation |
|---|---|
| bin | 11001100100010001010001… |
| … | …011011110010111110000000 |
| 3 | 112202010111121111222002210000 |
| 4 | 121210101101123302332000 |
| 5 | 104214234003133103212 |
| 6 | 1035051514211440000 |
| 7 | 32453532323321043 |
| oct | 3144212133627600 |
| 9 | 482114544862700 |
| 10 | 112443610050432 |
| 11 | 32912081524771 |
| 12 | 107403a95b6000 |
| 13 | 4a9850511501b |
| 14 | 1daa42a7a8c5a |
| 15 | ceedb29ba1dc |
| hex | 6644516f2f80 |
112443610050432 has 320 divisors, whose sum is σ = 346447653750000. Its totient is φ = 36159653117952.
The previous prime is 112443610050389. The next prime is 112443610050433. The reversal of 112443610050432 is 234050016344211.
112443610050432 is a `hidden beast` number, since 1 + 1 + 2 + 4 + 4 + 3 + 610 + 0 + 5 + 0 + 4 + 32 = 666.
It is a super-3 number, since 3×1124436100504323 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112443610050433) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 375389619 + ... + 375689037.
Almost surely, 2112443610050432 is an apocalyptic number.
112443610050432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112443610050432, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (173223826875000).
112443610050432 is an abundant number, since it is smaller than the sum of its proper divisors (234004043699568).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112443610050432 is a wasteful number, since it uses less digits than its factorization.
112443610050432 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 300723 (or 300702 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 36.
Adding to 112443610050432 its reverse (234050016344211), we get a palindrome (346493626394643).
The spelling of 112443610050432 in words is "one hundred twelve trillion, four hundred forty-three billion, six hundred ten million, fifty thousand, four hundred thirty-two".
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