Base | Representation |
---|---|
bin | 1010001110100100110010… |
… | …1001001100111010111011 |
3 | 1110211001121221111121111222 |
4 | 2203221030221030322323 |
5 | 2433221301111001141 |
6 | 35530041024142255 |
7 | 2240314140653411 |
oct | 243511451147273 |
9 | 43731557447458 |
10 | 11245510250171 |
11 | 364621540370a |
12 | 131755676798b |
13 | 6375a7287b32 |
14 | 2ac3dd9892b1 |
15 | 1477c525c14b |
hex | a3a4ca4cebb |
11245510250171 has 2 divisors, whose sum is σ = 11245510250172. Its totient is φ = 11245510250170.
The previous prime is 11245510250113. The next prime is 11245510250189. The reversal of 11245510250171 is 17105201554211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11245510250171 - 238 = 10970632343227 is a prime.
It is not a weakly prime, because it can be changed into another prime (11245510220171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5622755125085 + 5622755125086.
It is an arithmetic number, because the mean of its divisors is an integer number (5622755125086).
Almost surely, 211245510250171 is an apocalyptic number.
11245510250171 is a deficient number, since it is larger than the sum of its proper divisors (1).
11245510250171 is an equidigital number, since it uses as much as digits as its factorization.
11245510250171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14000, while the sum is 35.
The spelling of 11245510250171 in words is "eleven trillion, two hundred forty-five billion, five hundred ten million, two hundred fifty thousand, one hundred seventy-one".
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