Base | Representation |
---|---|
bin | 10100111100110000… |
… | …10001111111101011 |
3 | 1002000211101212112221 |
4 | 22132120101333223 |
5 | 141013224144013 |
6 | 5100012214511 |
7 | 545466525445 |
oct | 123630217753 |
9 | 32024355487 |
10 | 11247099883 |
11 | 4851770678 |
12 | 221a76a437 |
13 | 10a3192cb6 |
14 | 789a33495 |
15 | 45c5ee08d |
hex | 29e611feb |
11247099883 has 2 divisors, whose sum is σ = 11247099884. Its totient is φ = 11247099882.
The previous prime is 11247099839. The next prime is 11247099923. The reversal of 11247099883 is 38899074211.
It is a strong prime.
It is an emirp because it is prime and its reverse (38899074211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11247099883 - 29 = 11247099371 is a prime.
It is a super-2 number, since 2×112470998832 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11247099883.
It is not a weakly prime, because it can be changed into another prime (11247094883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5623549941 + 5623549942.
It is an arithmetic number, because the mean of its divisors is an integer number (5623549942).
Almost surely, 211247099883 is an apocalyptic number.
11247099883 is a deficient number, since it is larger than the sum of its proper divisors (1).
11247099883 is an equidigital number, since it uses as much as digits as its factorization.
11247099883 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 52.
The spelling of 11247099883 in words is "eleven billion, two hundred forty-seven million, ninety-nine thousand, eight hundred eighty-three".
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