Base | Representation |
---|---|
bin | 1010001110111010101000… |
… | …1110111110101011110001 |
3 | 1110211121202200211011212212 |
4 | 2203232222032332223301 |
5 | 2433320304100323323 |
6 | 35532451022501505 |
7 | 2240612366635526 |
oct | 243565216765361 |
9 | 43747680734785 |
10 | 11251375401713 |
11 | 3648755100897 |
12 | 1318712a34895 |
13 | 63800042b2c5 |
14 | 2ac7d88d514d |
15 | 147a1a109b78 |
hex | a3baa3beaf1 |
11251375401713 has 2 divisors, whose sum is σ = 11251375401714. Its totient is φ = 11251375401712.
The previous prime is 11251375401647. The next prime is 11251375401727. The reversal of 11251375401713 is 31710457315211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10255666787809 + 995708613904 = 3202447^2 + 997852^2 .
It is a cyclic number.
It is not a de Polignac number, because 11251375401713 - 28 = 11251375401457 is a prime.
It is not a weakly prime, because it can be changed into another prime (11251375401733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5625687700856 + 5625687700857.
It is an arithmetic number, because the mean of its divisors is an integer number (5625687700857).
Almost surely, 211251375401713 is an apocalyptic number.
It is an amenable number.
11251375401713 is a deficient number, since it is larger than the sum of its proper divisors (1).
11251375401713 is an equidigital number, since it uses as much as digits as its factorization.
11251375401713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 88200, while the sum is 41.
The spelling of 11251375401713 in words is "eleven trillion, two hundred fifty-one billion, three hundred seventy-five million, four hundred one thousand, seven hundred thirteen".
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