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112523053453 = 671679448559
BaseRepresentation
bin110100011001011100…
…1011000100110001101
3101202102220222101001021
41220302321120212031
53320421400202303
6123405315314141
711062266113266
oct1506271304615
9352386871037
10112523053453
11437a236a558
12199838ab951
13a7c313b545
14563631596d
152dd8878ebd
hex1a32e5898d

112523053453 has 4 divisors (see below), whose sum is σ = 114202502080. Its totient is φ = 110843604828.

The previous prime is 112523053441. The next prime is 112523053457. The reversal of 112523053453 is 354350325211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112523053453 is a prime.

It is a super-2 number, since 2×1125230534532 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112523053457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 839724213 + ... + 839724346.

It is an arithmetic number, because the mean of its divisors is an integer number (28550625520).

Almost surely, 2112523053453 is an apocalyptic number.

It is an amenable number.

112523053453 is a deficient number, since it is larger than the sum of its proper divisors (1679448627).

112523053453 is an equidigital number, since it uses as much as digits as its factorization.

112523053453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1679448626.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 112523053453 its reverse (354350325211), we get a palindrome (466873378664).

The spelling of 112523053453 in words is "one hundred twelve billion, five hundred twenty-three million, fifty-three thousand, four hundred fifty-three".

Divisors: 1 67 1679448559 112523053453