Base | Representation |
---|---|
bin | 10100111101011110… |
… | …10011100010001001 |
3 | 1002001020202111212012 |
4 | 22132233103202021 |
5 | 141021300313442 |
6 | 5100345425305 |
7 | 545602034132 |
oct | 123657234211 |
9 | 32036674765 |
10 | 11253135497 |
11 | 485511328a |
12 | 222079b235 |
13 | 10a44c7276 |
14 | 78a764c89 |
15 | 45cde2582 |
hex | 29ebd3889 |
11253135497 has 2 divisors, whose sum is σ = 11253135498. Its totient is φ = 11253135496.
The previous prime is 11253135449. The next prime is 11253135539. The reversal of 11253135497 is 79453135211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7621988416 + 3631147081 = 87304^2 + 60259^2 .
It is a cyclic number.
It is not a de Polignac number, because 11253135497 - 26 = 11253135433 is a prime.
It is not a weakly prime, because it can be changed into another prime (11253135427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5626567748 + 5626567749.
It is an arithmetic number, because the mean of its divisors is an integer number (5626567749).
Almost surely, 211253135497 is an apocalyptic number.
It is an amenable number.
11253135497 is a deficient number, since it is larger than the sum of its proper divisors (1).
11253135497 is an equidigital number, since it uses as much as digits as its factorization.
11253135497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 113400, while the sum is 41.
The spelling of 11253135497 in words is "eleven billion, two hundred fifty-three million, one hundred thirty-five thousand, four hundred ninety-seven".
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