Base | Representation |
---|---|
bin | 1010001111000001011100… |
… | …0101100010111101011011 |
3 | 1110211210110222012222021001 |
4 | 2203300113011202331123 |
5 | 2433333024110123103 |
6 | 35533352141325431 |
7 | 2241005553515254 |
oct | 243602705427533 |
9 | 43753428188231 |
10 | 11253201645403 |
11 | 3649501a5a7a3 |
12 | 1318b42566877 |
13 | 6382318a9683 |
14 | 2ac92d27db2b |
15 | 147ac55e901d |
hex | a3c17162f5b |
11253201645403 has 2 divisors, whose sum is σ = 11253201645404. Its totient is φ = 11253201645402.
The previous prime is 11253201645377. The next prime is 11253201645467. The reversal of 11253201645403 is 30454610235211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11253201645403 is a prime.
It is not a weakly prime, because it can be changed into another prime (11253201645493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5626600822701 + 5626600822702.
It is an arithmetic number, because the mean of its divisors is an integer number (5626600822702).
Almost surely, 211253201645403 is an apocalyptic number.
11253201645403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11253201645403 is an equidigital number, since it uses as much as digits as its factorization.
11253201645403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 11253201645403 in words is "eleven trillion, two hundred fifty-three billion, two hundred one million, six hundred forty-five thousand, four hundred three".
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