Base | Representation |
---|---|
bin | 1010001111000010001110… |
… | …1010000101110111000111 |
3 | 1110211211000200002010220111 |
4 | 2203300203222011313013 |
5 | 2433333442103132020 |
6 | 35533425114013451 |
7 | 2241014024266555 |
oct | 243604352056707 |
9 | 43754020063814 |
10 | 11253412552135 |
11 | 3649600012086 |
12 | 1318ba1117287 |
13 | 6382664b2160 |
14 | 2ac94d2a0bd5 |
15 | 147ad8da9d5a |
hex | a3c23a85dc7 |
11253412552135 has 64 divisors (see below), whose sum is σ = 15549495736320. Its totient is φ = 7749697835520.
The previous prime is 11253412552037. The next prime is 11253412552139. The reversal of 11253412552135 is 53125521435211.
11253412552135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11253412552135 - 223 = 11253404163527 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11253412552139) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 20978365 + ... + 21508105.
It is an arithmetic number, because the mean of its divisors is an integer number (242960870880).
Almost surely, 211253412552135 is an apocalyptic number.
11253412552135 is a deficient number, since it is larger than the sum of its proper divisors (4296083184185).
11253412552135 is a wasteful number, since it uses less digits than its factorization.
11253412552135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 530048.
The product of its digits is 180000, while the sum is 40.
Adding to 11253412552135 its reverse (53125521435211), we get a palindrome (64378933987346).
The spelling of 11253412552135 in words is "eleven trillion, two hundred fifty-three billion, four hundred twelve million, five hundred fifty-two thousand, one hundred thirty-five".
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